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February 22, 2008
Ex-House leader to be sentenced, asks for leniency
PROVIDENCE -- Former House Majority Leader Gerard M. Martineau, who is scheduled to be sentenced today on federal corruption charges, is asking the sentencing judge for leniency.
Martineau, a longtime state representative from Woonsocket who did not run for reelection in 2002, pleaded guilty in November to corruption charges for steering legislation that benefited the CVS drugstore chain and Blue Cross & Blue Shield of Rhode Island, with which he had plastic and paper bag contracts worth more than $800,000.
Martineau’s sentencing is scheduled for 9:30 a.m. before U.S. District Judge Mary M. Lisi.
Martineau’s lawyer, William P. Devereaux, filed a motion with the court seeking a lenient sentence, citing Martineau’s record as a businessman, legislator and “devoted family man.”
“In this case, the Court has before it a man who is truly remorseful; recognizes that he must be held accountable; but asks the Court for consideration of how he has lived his life in comparison to the unfortunate events which have brought him before this Court,” the motion says.
Martineau faces up to 46 months in prison and a maximum fine of $1.8 million for each count.
Posted by Jack Perry
at 7:01 AM | Permalink
robert ferland | February 22, 2008 11:02 AM link
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He betrayed the trust of those that supported him. Maximum sentence and recoup the money he gathered from his corrupt undertakings